Question

For z = 2cis pi/6, find z^5 in rectangular form

Answer 1

@wolfd.andi

Answer 2

@Anon101

Answer 3

Recall DeMoivre's theorem:
\[\newcommand{cis}{\,\text{cis}\,}\Large \left(re^{it}\right)^n=\left(r\cis t\right)^n=r^n\cis nt=r^ne^{int}\]