Hi guys.
I am looking for the equation of the tangent line to y=4sin(x) at x=3pi/4.
I took the deriv of 4sin(x) and got 4cos(x). plugged it into the equation and got:
y-(4(sqrt2)/2 = (-4(sqrt2)/2)(x-(3pi/4).
now I am stuck.......suggestions?

Question

Hi guys.
I am looking for the equation of the tangent line to y=4sin(x) at x=3pi/4.
I took the deriv of 4sin(x) and got 4cos(x). plugged it into the equation and got:
y-(4(sqrt2)/2 = (-4(sqrt2)/2)(x-(3pi/4).
now I am stuck.......suggestions?

anonymous · Answer

$$y-(4\sqrt{2)}/2 = -((4\sqrt{2)}/2)(x-3\pi/4)$$