Question

Help?? Will fan and medal
attached below

Answer 1

\[A=2(wl+hl+hw)\]

Answer 2

now just plug in your numbers

Answer 3

ok is w 4?

Answer 4

and the length 3?

Answer 5

they're arbitrary. as long as you stick with what you pick, it comes out to the same thing I think

Answer 6

lemme try this with your numbers and mine

Answer 7

I got 32

Answer 8

A=2(wl+hl+hw)
mine: w=2,h=4,l=3
A=2(wl+hl+hw)=\((2*3+4*3+4*2)=6+12+8=26\)

yours: w=4,h=2,l=3
A=2(wl+hl+hw)=12+6+6=20

ok, I lied

Answer 9

Oh I multiplied something wrong

Answer 10

wait I forgot to multiply by 2 on both counts

Answer 11

A=2(wl+hl+hw)
mine: w=2,h=4,l=3
A=2(wl+hl+hw)=(2∗3+4∗3+4∗2)=6+12+8=26

yours: w=4,h=2,l=3
A=2(wl+hl+hw)=12+6+8=26

ok, I lied

Answer 12

I got 26

Answer 13

so that means we're both right, 2(26)=52

Answer 14

Is it 52m^2?

Answer 15

aye aye
because A=2(wl+hl+hw)=\(2((4m*3m)+(2m*3m)+(4m*2m))=2(12m^2+6m^2+8m^2)=2(26m^2)=52m^2\)

Answer 16

52m^2

Answer 17

yeeeeeeeeeeee thank u bib

Answer 18

no, no thank

Answer 19

YOU

Answer 20

<3

Answer 21

\(\huge \color{pink}\heartsuit\)