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Mathematics 14 Online
OpenStudy (anonymous):

What are the exact solutions of x2 - 3x - 1 = 0? x = the quantity of 3 plus or minus the square root of 5 all over 2 x = the quantity of negative 3 plus or minus the square root of 5 all over 2 x = the quantity of 3 plus or minus the square root of 13 all over 2 x = the quantity of negative 3 plus or minus the square root of 13 all over 2

OpenStudy (bloomlocke367):

do you know the quadratic formula?

OpenStudy (bloomlocke367):

you could use that method.

OpenStudy (bloomlocke367):

\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

OpenStudy (anonymous):

a=1 b= -3x c=-1

OpenStudy (anonymous):

is that what i would plug in?

OpenStudy (bloomlocke367):

yes, but b is just -3

OpenStudy (bloomlocke367):

\[x=\frac{ 3 \pm \sqrt{9-4(1)(-1)} }{ 2 }\]

OpenStudy (anonymous):

i tried to do that srry

OpenStudy (bloomlocke367):

it's okay :) can you solve the rest, or do I need to walk you through it?

OpenStudy (anonymous):

if you could walk me through it please

OpenStudy (bloomlocke367):

okay well what's -4*1*-1?

OpenStudy (anonymous):

would it be sqrt 9--4?

OpenStudy (anonymous):

Wait is it C?

OpenStudy (bloomlocke367):

\[x=\frac{ 3 \pm \sqrt{9+4} }{ 2 }\]\[x=\frac{ 3 \pm \sqrt{13}}{ 2 }\]

OpenStudy (bloomlocke367):

yes, it is C good job :)

OpenStudy (anonymous):

thats C! thank you so much

OpenStudy (bloomlocke367):

you're welcome XD

OpenStudy (anonymous):

I became a fan :3

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