Mathematics
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OpenStudy (anonymous):
Which polynomial expression represents the area of the outermost square tile, shown below?
A square shaped tile with length x plus three is shown
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OpenStudy (anonymous):
OpenStudy (anonymous):
@xapproachesinfinity
OpenStudy (xapproachesinfinity):
what is the area of a square, do you know?
OpenStudy (xapproachesinfinity):
so?!!
OpenStudy (anonymous):
no
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OpenStudy (xapproachesinfinity):
well you should know!!
\[\rm area~of~a~square=a^2\]
where a is the length of the square's side
OpenStudy (anonymous):
sorry i forgot
OpenStudy (xapproachesinfinity):
so A=a^2 that is the area of the square
what think that you cannot forgot is the area of a square and rectangle
OpenStudy (xapproachesinfinity):
otherwise doing algebra without this is meaningless
OpenStudy (xapproachesinfinity):
that being said!
here we have a square that has a side if x+3
so the Area would be
\[\rm A=(x+3)^2\]
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OpenStudy (xapproachesinfinity):
expand that
OpenStudy (anonymous):
9
OpenStudy (xapproachesinfinity):
9? why?? we have x+3 where did you come up with 9
OpenStudy (xapproachesinfinity):
tell me you know how to expand the binomial
\[(a+b)^2\]
OpenStudy (anonymous):
are u there
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OpenStudy (xapproachesinfinity):
\[(a+b)^2=a^2+2ab+b^2\]
OpenStudy (xapproachesinfinity):
I'm here :) why ? lol
OpenStudy (xapproachesinfinity):
the same thing with \[(x+3)^2\]
OpenStudy (anonymous):
ab^2
OpenStudy (anonymous):
3^2 that's how
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OpenStudy (anonymous):
lol im confused
OpenStudy (xapproachesinfinity):
hmm no my friend
you have to expand the binomial
don't tell you are doing polynomial while you don't have any idea how to expand binomials?
OpenStudy (anonymous):
i forgot how to do all of this i had to retake thisclass because i failed it
OpenStudy (xapproachesinfinity):
\[(a+b)^2=(a+b)(a+b)=a^2+ab+ba+b^2=a^2+2ab+b^2\]
this is how you expand the binomial
OpenStudy (xapproachesinfinity):
well you can't just go and do the problem without reviewing!!
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OpenStudy (anonymous):
what is the next step
OpenStudy (xapproachesinfinity):
do the same thing that i did with (a+b)^2
but now you have (x+3)^2
instead
so x instead of a and 3 instead of b
OpenStudy (anonymous):
ok
OpenStudy (xapproachesinfinity):
ok show me you work
OpenStudy (anonymous):
x^2 +6x
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OpenStudy (anonymous):
+6
OpenStudy (anonymous):
am i correct
OpenStudy (anonymous):
hello
OpenStudy (anonymous):
@pooja195 @charlotte123
OpenStudy (xapproachesinfinity):
no!!
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OpenStudy (xapproachesinfinity):
\[(x+3)^2=x^2+6x+9\]
OpenStudy (anonymous):
ok so
OpenStudy (anonymous):
x^2-6
OpenStudy (anonymous):
x^2-6x+9
OpenStudy (anonymous):
@xo_kansasprincess_xo
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OpenStudy (anonymous):
@xapproachesinfinity
OpenStudy (anonymous):
ughh forget it
OpenStudy (xapproachesinfinity):
i just gave you the ANSWER