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Mathematics 7 Online
OpenStudy (anonymous):

Which polynomial expression represents the area of the outermost square tile, shown below? A square shaped tile with length x plus three is shown

OpenStudy (anonymous):

OpenStudy (anonymous):

@xapproachesinfinity

OpenStudy (xapproachesinfinity):

what is the area of a square, do you know?

OpenStudy (xapproachesinfinity):

so?!!

OpenStudy (anonymous):

no

OpenStudy (xapproachesinfinity):

well you should know!! \[\rm area~of~a~square=a^2\] where a is the length of the square's side

OpenStudy (anonymous):

sorry i forgot

OpenStudy (xapproachesinfinity):

so A=a^2 that is the area of the square what think that you cannot forgot is the area of a square and rectangle

OpenStudy (xapproachesinfinity):

otherwise doing algebra without this is meaningless

OpenStudy (xapproachesinfinity):

that being said! here we have a square that has a side if x+3 so the Area would be \[\rm A=(x+3)^2\]

OpenStudy (xapproachesinfinity):

expand that

OpenStudy (anonymous):

9

OpenStudy (xapproachesinfinity):

9? why?? we have x+3 where did you come up with 9

OpenStudy (xapproachesinfinity):

tell me you know how to expand the binomial \[(a+b)^2\]

OpenStudy (anonymous):

are u there

OpenStudy (xapproachesinfinity):

\[(a+b)^2=a^2+2ab+b^2\]

OpenStudy (xapproachesinfinity):

I'm here :) why ? lol

OpenStudy (xapproachesinfinity):

the same thing with \[(x+3)^2\]

OpenStudy (anonymous):

ab^2

OpenStudy (anonymous):

3^2 that's how

OpenStudy (anonymous):

lol im confused

OpenStudy (xapproachesinfinity):

hmm no my friend you have to expand the binomial don't tell you are doing polynomial while you don't have any idea how to expand binomials?

OpenStudy (anonymous):

i forgot how to do all of this i had to retake thisclass because i failed it

OpenStudy (xapproachesinfinity):

\[(a+b)^2=(a+b)(a+b)=a^2+ab+ba+b^2=a^2+2ab+b^2\] this is how you expand the binomial

OpenStudy (xapproachesinfinity):

well you can't just go and do the problem without reviewing!!

OpenStudy (anonymous):

what is the next step

OpenStudy (xapproachesinfinity):

do the same thing that i did with (a+b)^2 but now you have (x+3)^2 instead so x instead of a and 3 instead of b

OpenStudy (anonymous):

ok

OpenStudy (xapproachesinfinity):

ok show me you work

OpenStudy (anonymous):

x^2 +6x

OpenStudy (anonymous):

+6

OpenStudy (anonymous):

am i correct

OpenStudy (anonymous):

hello

OpenStudy (anonymous):

@pooja195 @charlotte123

OpenStudy (xapproachesinfinity):

no!!

OpenStudy (xapproachesinfinity):

\[(x+3)^2=x^2+6x+9\]

OpenStudy (anonymous):

ok so

OpenStudy (anonymous):

x^2-6

OpenStudy (anonymous):

x^2-6x+9

OpenStudy (anonymous):

@xo_kansasprincess_xo

OpenStudy (anonymous):

@xapproachesinfinity

OpenStudy (anonymous):

ughh forget it

OpenStudy (xapproachesinfinity):

i just gave you the ANSWER

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