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Evaluate and put answer in radians. a.) arctan(-sqrt3) b.) Arctan(-sqrt3) my answer: -pi/2 Arcsin(x) pi/2 0 Arccos(x) pi pi/2 Arctan(x) pi/2 arctan(-sqrt3)=-pi/3+2n pi Arctan(-sqrt3)=-pi/3 is this correct?
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