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will fan and medal for help, attached below
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\(SA_{cylinder}=2 \pi r^2 + 2 \pi rh\) you can think of this as 2 circles (the top and bottom) and then the area of the rectangle wrapped around.
so, let's do 3 first, h = 16 r=8
\(2 \pi *64+2 \pi *8*16=128 \pi + 256 \pi = 384 \pi\)
ok i drew it out
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wut which one, no drawing necessary
#3, its just easier for me to learn by drawing it out xD
oh, alright lol. I won't question her grace's methods
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visually, unwrapping the cylinder gives you a rectangle and 2 circles.
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