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Question 8! http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s08_qp_3.pdf
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Apparently y/TN = dy/dx How is this?
Let b be the base length of the triangle \[dy/dx=y/b\] \[b=ydx/dy\] \[(yb)/2=tanx\] \[y^2dx/dy=2tanx\] \[dy/dx=y^2cotx/2\] See its simple
what's b?
you see the slope of tangent is dy/dx which is equal to tanx which is again equalyto x/TN i have taken TN as b
is b x?
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no b is TN
TN is x no?
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