Simplify completely 12 times x to the third power minus 4 times x to the 2nd power plus 8 times x all over negative 2 times x

Question

anonymous · Answer

@StudyGurl14

studygurl14 · Answer

$\Large\frac{12x^3-4x^2+8x}{-2x}$

Okay, for this one, you want to do the same thing - eliminate the denominator. Do you remember how to do that?

anonymous · Answer

I have 3 more after this thank u for helping me while everyone else just watchs and never helps

anonymous · Answer

no i do not get this

anonymous · Answer

i just need help with 3 more questions

studygurl14 · Answer

I'll walk you through it one more time. 

First Step: factor out the the denominator from the numerator, in this case, -2x

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So...
$\Large\frac{12x^3-4x^2+8x}{-2x}\rightarrow\frac{-2x(-6x^2+2x-4)}{-2x}$

What's the next step?