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OpenStudy (anonymous):
PLEASE HELP =)
Write x2 - 6x + 7 = 0 in the form (x - a)2 = b, where a and b are integers.
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OpenStudy (anonymous):
(x - 4)2 = 3
(x - 3)2 = 2
(x - 2)2 = 1
(x - 1)2 = 4
rishavraj (rishavraj):
-6x = 2*(-3)*x
rishavraj (rishavraj):
proceed
OpenStudy (anonymous):
Uhhhhh sorry =)
rishavraj (rishavraj):
for wth????o_O @CountryGurl15
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OpenStudy (anonymous):
I'm sorry you said proceed and idk what to do next =)
rishavraj (rishavraj):
(x - a)^2 = x^2 + a^2 - 2ax
see the term having negative sign is formed by multiplying all given terms with 2....
OpenStudy (anonymous):
Oh okay =)
rishavraj (rishavraj):
here u r having -6x which mean its 2*(-3)x
rishavraj (rishavraj):
so u got "a"
a = 3
proceed
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OpenStudy (anonymous):
Ohhh okay so we get -5x
rishavraj (rishavraj):
wht u mean???
in (x - a)^2
a = 3.......
OpenStudy (anonymous):
I'm sorry if that's wrong, i'm trying to get this i really am =)
OpenStudy (anonymous):
oh so it's (x-3)^2 ?
rishavraj (rishavraj):
nah...
u r close..see in question given equation is x2 - 6x + 7 = 0
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OpenStudy (anonymous):
(x-3)^2 = 2?
OpenStudy (anonymous):
Yes. . . . .
rishavraj (rishavraj):
@CountryGurl15 bingo u r right...:))
OpenStudy (anonymous):
Thanks so much! =)
rishavraj (rishavraj):
u r most welcome......:)
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