The equation for the height of an object thrown though the air is h= -4t^2 + 48t + 7, where h is the height in feet and t is the time in seconds.

How long will it take the object to reach maximum height? (Hint: eight seconds was a part of this a,b,c,d question)

Question

The equation for the height of an object thrown though the air is h= -4t^2 + 48t + 7, where h is the height in feet and t is the time in seconds. 

How long will it take the object to reach maximum height? (Hint: eight seconds was a part of this a,b,c,d question)

anonymous · Answer

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