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Calculus1
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Evaluate ∫ (1/2)x^(2) sin(x^3) dx
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Hint : there is a very obvious \(u\) substitution
-1/6 cos (x^3)
ok so i got u=x^(3) du=3x^(2) (1/3)du=x^(2) and I got -1/3 cos(x^3)+c . Was -1/3 multiplied nby 1/2 to get -1/6?
nvm I got it thanks
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