WILL MeDAL AND FAN
[4.01] Find the value of x.
A triangle drawn with a midsegment labeled x. The side parallel to the midsegment is labeled 60. (3 points)
40
30
10
20
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OpenStudy (anonymous):
hi jhanny!
OpenStudy (anonymous):
OpenStudy (anonymous):
oops srry
OpenStudy (jhannybean):
Well, you'd want to make a ratio between the two similar triangles
OpenStudy (anonymous):
how, pray explain, do i do that?
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OpenStudy (jhannybean):
/O?r rather, if it's the midsegment of the triangle, wouldnt that mean that it's splitting the bigger triangle in half?
OpenStudy (jhannybean):
So length x is \(\frac{1}{2}\) the length of the base of the big triangle 60?
OpenStudy (anonymous):
yes that is true, but the lines on either side are not congruent. therefore, the lenths must be different, am i correct?
OpenStudy (jhannybean):
They are congruent...
OpenStudy (jhannybean):
|dw:1426245499319:dw|
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OpenStudy (jhannybean):
Think of each side as a component. If you're matching up components, then you're matching up side to side.
OpenStudy (jhannybean):
Therefore, since x is a midsegment of the bigger triangle with base 60, we can use similar triangles to match up the base of the smaller triangle to the base of the larger triangle because they are congruent.
OpenStudy (jhannybean):
Therefore \(x=\frac{1}{2}(60)\)
OpenStudy (anonymous):
srry was at the bthroom
OpenStudy (anonymous):
cool thx! but please tell me how to find the ratio of an object
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OpenStudy (igreen):
@Jhannybean I think you mean 'they're similar**'
Congruent means they're exactly the same..
OpenStudy (anonymous):
exactly :3
OpenStudy (jhannybean):
Sorry, yes you are correct. similar rather than conguent.
OpenStudy (igreen):
Lol
OpenStudy (jhannybean):
It's 4:30 AM..... :(
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OpenStudy (igreen):
Oh, it's almost 7:30AM here
OpenStudy (anonymous):
6:24am :(
OpenStudy (anonymous):
i should be asleep!
OpenStudy (igreen):
xD
OpenStudy (jhannybean):
Same.
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OpenStudy (igreen):
Not me :P
OpenStudy (anonymous):
my mom is making me do 9 geometry assignments today DX
OpenStudy (jhannybean):
Yuck.
OpenStudy (anonymous):
anyway thx fr ur help
OpenStudy (jhannybean):
No problem :)
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