Question

Perform the indicated Operations

(a+ 3)^2/ a -3 divided by 5/ (a^2 - 9)

Answer 1

What i have so far is\[\frac{ (a+3)(a+3) }{ a-3 }\div \frac{ 5 }{ a^2-9 }\]

Answer 2

\[\frac{(a+3)^2}{\frac{5 (a-3)}{a^2-9}}=\frac{(a+3)^2}{\frac{5 (a-3)}{(a+3) \{a-3\}}}=\frac{1}{5} (a+3)^3 \]a-3 divides out.

Answer 3

Im still a little confused.

Answer 4

\[\huge\rm \frac{ (a+3)(a+3) }{ a-3 }\div \frac{ 5 }{ a^2-9 }\]
change division to multiplication
for example \[\huge\rm \frac{ a }{ b } \div \frac{ c }{ d } = \frac{ a }{ b } \times \frac{ d }{ c }\]
multiply first fraction by reciprocal of 2nd one

Answer 5

apply difference of square method
\[\huge\rm (a^2 - b^2) = (a+b)(a-b)\]