Question

http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20%289709%29/9709_s13_qp_31.pdf
Q4ii)

Answer 1

thats for part i) square both sides (4x-1)^2=(x-3)^2,16x^2-8x+1=x^2-6x+9, 15x^2-2x-8 x1=4/5 x2=-2/3 Check solutions
(4(4/5)-1)=mod(4/5-3)11/5=11/5 true solutionmod(4(-2/3)-1)=mod(x-3)11/3=11/3 true solution

Answer 2

so if you are happy with your answer, then x = 4^y as 4x = 4.4^y = 4 ^ (y+1)

Answer 3

Thanks @IrishBoy123 :)