Find an equation of a line tangent to y = 2sin x whose slope is a maximum value in the interval (0, 2π]
I believe the equation is y=2x-4pi. How is the b-value -4pi?

Question

Find an equation of a line tangent to y = 2sin x whose slope is a maximum value in the interval (0, 2π]
I believe the equation is y=2x-4pi. How is the b-value -4pi?

anonymous · Answer

this just a sin curve max slope at (0,0) =1
so y =2x
I think

anonymous · Answer

T got that too. But I was told that the b value is -4pi. I'm not sure where that number came about

anonymous · Answer

*I got that too

jtvatsim · Answer

I think what is going on here is that they are preventing you from using the "easy answer" of y = 2x. Notice that y = 2x passes through 0 which is not allowed by the interval (0, 2pi].

jtvatsim · Answer

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