The product of 3 different integers is equal to 7^3. What is the sum?

Question

rizags · Answer

do you want the answer or an explanation or both

anonymous · Answer

So far I have done this:

x * (x+1) * (x+2) = 7^3
(x^2+x) * (x+2) = 7^3
x^3 + 3x^2 + 2x = 7^3

However when I try to solve for x I get an irrational number.

I want both an answer and the explanation.

rizags · Answer

no good. you're making it way too complicated

rizags · Answer

first, i want you to evaluate 7^3 and give me all factors in ascending order

rizags · Answer

btw what grade and what class is this for?

anonymous · Answer

7^3 = 343

All the factors of 343 are:
1,7,49,343

I am in 10th grade and learning algebra 1 and algebra 2.

rizags · Answer

ok cool, me too. anyway, since it is identified that those numbers are DIFFERENT, that means that they must all be factors of 343, therefore, i want you to look at those factors and pick out the 3 that work!

anonymous · Answer

1*7*49=343

So the sum of these factors is 57.

rizags · Answer

yes! medal plzz and fan