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Triangle ABC is shown in the figure below. The measure of ∠A is 40°, AB = 18 cm, and AC = 12 cm. Which of the following is the length, in centimeters, of BC? I have the answer, but I don't understand it.
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The answer is \[{\sqrt{12^{2}+18^{2}-(2)(18)(12)\cos 40}}\]
heard of Cosine rule?
Yes, but I dont know how to apply it
http://www.mathsisfun.com/algebra/trig-cosine-law.html draw your triangle on the paper first :)
|dw:1426435038177:dw| like that ^^ now name the lengths and angles
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