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\[\sqrt{3} cscx+2=0 \]
so minus 2 and divide by sq rt of 3, then what?
What is the given or desired domain for x here ?
No specification.
"general solution"..should be two answers
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Then let's use 0 to 2 pi , in radians. Your first two steps you typed are a great start!
With csc=-2/sqrt3, do I change this to sin..?
\[cscx \space = \frac{ -2 }{ \sqrt{3} }\]
yes, that is the correct next step
\[\frac{ 1 }{ sinx } \space = \frac{ -2 }{ \sqrt{3} }\]
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rearrange that and get sin x up into the top now
i think you have to switch it
yeah
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