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Mathematics 8 Online
OpenStudy (dtan5457):

Find the general solution

OpenStudy (dtan5457):

\[\sqrt{3} cscx+2=0 \]

OpenStudy (dtan5457):

so minus 2 and divide by sq rt of 3, then what?

Miracrown (miracrown):

What is the given or desired domain for x here ?

OpenStudy (dtan5457):

No specification.

OpenStudy (dtan5457):

"general solution"..should be two answers

Miracrown (miracrown):

Then let's use 0 to 2 pi , in radians. Your first two steps you typed are a great start!

OpenStudy (dtan5457):

With csc=-2/sqrt3, do I change this to sin..?

Miracrown (miracrown):

\[cscx \space = \frac{ -2 }{ \sqrt{3} }\]

Miracrown (miracrown):

yes, that is the correct next step

Miracrown (miracrown):

\[\frac{ 1 }{ sinx } \space = \frac{ -2 }{ \sqrt{3} }\]

Miracrown (miracrown):

rearrange that and get sin x up into the top now

OpenStudy (dtan5457):

i think you have to switch it

OpenStudy (dtan5457):

yeah

OpenStudy (ybarrap):

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