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1/4+x-3/8=5/8
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if you add 3/8 to both sides you end up with 1/4+x=1, therefore x must be 3/4
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\[\frac{ 1 }{ 4 } + \frac{ x-3 }{ 8 } =\frac{ 5 }{ 8 }\]
\[\frac{ 2+(x-3) }{ 8 } = \frac{ x-1 }{ 8 } \]
\[x-1=5 \]
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\[x=6\]
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