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Find the last \(3\) digits of \(11^{402}\)
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ahh its 11 so!
|dw:1426494811029:dw|
there shud be some cascading pattern we can work of
xD
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the first 3 are nice
pascal triangle stuff coming up
last two digits have a neat pattern
but this problem is supposed to be easy after working euler generalization to fermats little thm yesterday
oh cool its pascal all the waY!!!
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|dw:1426495127854:dw|
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