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What are the dimensions of the following rectangle?
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A. -6 2/3, -18 B. -6 2/3, 6 C. 6 D. 6, 20
A= L times B Where 'A' is area 'L' is length 'B; is breath or width/(w)
So now We get 120 = (3x + 2)(x) Solve for 'x' First.
120 = 3x^2 + 2x
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i dont understand how to get the answer?
OKAY! We will use the first method then. SO the eqn we had obtained was 120 = x^2 + 2x right?
yea
so now 120 = 3x^2 + 2x equate the eqn to 0
i.e 3x^2 + 2x -120 = 0
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On solving we get x = -20/3 = 6 2/3 and x = 6
So the correct ans is B
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