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\[-2\sqrt{x}=2x-\frac{ 3 }{ 2 }\]
\(\large\color{black}{ \displaystyle -2\sqrt{x}=2x-\frac{3}{2} }\) \(\large\color{black}{ \displaystyle \left(-2\sqrt{x}\right)^2=\left(2x-\frac{3}{2}\right)^2 }\) \(\large\color{black}{ \displaystyle 4x=4x^2-(2)\frac{3}{2}(2x)+\frac{9}{4} }\) \(\large\color{black}{ \displaystyle 4x=4x^2-6x+\frac{9}{4} }\) \(\large\color{black}{ \displaystyle 0=4x^2-10x+\frac{9}{4} }\) and on... negative solutions will be extraneous, considering the initial equation.
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