Question

help me please
Which system of equations does not have a real solution?

y = x **2 + 3x - 5 and x + y = -10
y = x **2 + 3x - 5 and 4x + 5y = 20
y = x **2+ 3x- 5 and x + y = -9

Answer 1

please be nice and someone help me

Answer 2

which do you think

Answer 3

@LmL

Answer 4

I dont know :(

Answer 5

damn my sleek-feathered one?<gone help you

Answer 6

pretty asf

Answer 7

told you bruh

Answer 8

: x = 2y - 2 and 3x - y = 14
3(2y-2)-y=14 substitute x in first for x in second and distribute the 3
6y-6-y=14 combine like terms
5y=20 divide by 5
y=4 (only one with y=4 is the first, so that one. But I'll solve for x so you know how to)

x=2(4)-2
x=8-2
x=6
(6,4)


2m - 3n = 6 and m = 3 - 2n
2(3-2n)-3n=6 substitute m in second for m in first and distribute the 2
6-4n-3n=6 combine like terms
-7n=0 divide by -7
n=0 (again only one with n=0 is second, but I will solve for m)

m=3-2(0)
m=3
(3,0)


4x + y = 4 and y = 4 - 4x
4x+4-4x=4 substitute y in second for y in first
4=4 infinitely many solutions


x = 4y and 2x + 3y = 44
2(4y)+3y=44
8y+3y=44
11y=44
y=4

x=4(4)
x=16
(16,4)


a + b = 4 and 2a + 3b = 11
b=-a+4

2a+3(-a+4)=11
2a-3a+12=11
-a+12=11
-a=-1
a=1

1+b=4
b=3
(1,3)


y = 1 - 5x and 5x + y = 8
5x+1-5x=8
0=7 no solution


3a - b = 11 and 2a + 3b = 0
-b=-3a+11
b=3a-11

2a+3(3a-11)=0
2a+9a-33=0
11a=33
a=3

2(3)+3b=0
6+3b=0
3b=-6
b=-2
(3,-2)

Answer 9

your welcome

Answer 10

Thanks :)