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New question what is the vertex of f(x)=x^2+10x+16? A)(2,6) B)(1,5) C)(5,9) D)(-5,-9)
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HHI!!!
the first coordinate of the vertex of \(y=ax^2+bx+c\) is \(-\frac{b}{2a}\) which in your case is \[-\frac{10}{2\times 1}\]
there is only one choice with \(-5\) as the x coordinate, so you don't have to find the second coordinate
so the correct answer is D?
lol yeah that is the only one with a -5 in the first slot right?
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yea
lol just reassuring in case someone has this same question and they wnt to answer it quickly
thank you :D!
you welcome
so how old are u
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