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Using the graph of f(x) = log2x below, approximate the value of y in the equation 22y = 3. HALP! Will fan and medal…
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is that log2x or log base 2 of x
\[f(x)=\log_{2}x \]
and the other is \[2^{2y}\]
thank you
It gives me these options… y ≈ 4.01 y ≈ .79 y ≈ 1.58 y ≈ 0.47
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give us the graph ?
I'm so confused /).(\
hold on
it makes sense now
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\[2^{2y}=3\] this is a function of y which gives the value x let x=3 so look at the graph, and draw x=3 |dw:1426538201255:dw|
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