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√(2-(-1))^2+(-1-2)^2 I know the answer is 4.24, but I don't know how to get there
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\[\sqrt{(2-(-1))^{2}+(-1-2)^{2}}\] okay so 2--1=2+1=3 -1-2=3 so you get \[\sqrt{(3)^{2}+(-3)^{2}}\]
you can finish this I am sure
-1-2=-3 sorry typo of the sign
But they cancel each other out right?
9+(-9)= 0 so I just end up with √0
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\[\huge\rm (-3)^2 = ??\]
Thanks I got it
if you have even even exponent of negative number ansawer always going to be POSITIVE and if u have odd number of exponent of negative number answer always going to be NEGATIVE
sorry openstudy is always so slow I only just got the notification of the reply thank you @Nnesha
np :) btw i didnb't do anything thanks to you :) you helped her not mehh
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