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Mathematics
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pooja195 (pooja195):
Simplify
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pooja195 (pooja195):
\[(\frac{ 7x^-2y }{ x^8y-5})^3\]
OpenStudy (e.mccormick):
And?
OpenStudy (e.mccormick):
Ah. Simplify. OK. Then you need to get things factored so they can cancel.
pooja195 (pooja195):
I started this today im confused i have no idea what to do ;-; do i distribute the 3?
TheSmartOne (thesmartone):
Here is the question written correctly in latex :P
\(\Large(\frac{ 7x^{-2}y }{ x^{8}y^{-5}})^3\)
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pooja195 (pooja195):
im not a LaTex genius :P
TheSmartOne (thesmartone):
Well first off
\(\Large a^x \times a^y = a^{x+y}\)
\(\Large a^{-x}=\frac{1}{a^x}\)
\(\Large\frac{a^b}{a^c}=a^{b-c}\)
pooja195 (pooja195):
so i do distribute?
OpenStudy (e.mccormick):
If the whole thing is ^3, that does not matter at the moment.
Though, I think we are not seeing the question quite as asked...
TheSmartOne (thesmartone):
Well first lets use the second formula and simplify \(\ x^{-2}\) and the \(y^{-5}\)
We will at the end then do the ^3
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OpenStudy (e.mccormick):
If it is as TSP says, then yah, all you need are those rules.
pooja195 (pooja195):
TSP xD um...so i x^-2+8?
TheSmartOne (thesmartone):
Yup!
And what is -2+8=?
And remember this value is going to be in the denominator.
pooja195 (pooja195):
ok nvm i have it thanks!! :D
TheSmartOne (thesmartone):
Np then :)
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