Question

Determine the vector equation of a line passing through the point P(3,2,-1) and with a direction vector perpendicular to the line r=(2,-3,4)+s(1,1,-2), seR

Answer 1

you want the vector equation of a line that is perpendicular to vector (1,1,-2) and contains the point (3,2,-1)

Answer 2

ok but i don't know how to start the answer

Answer 3

would I find the x, y and z values?

Answer 4

you need to find a solution to
(1,1,-2) . (a,b,c) = 0

Answer 5

(1,1,1) works

Answer 6

ok and is that the dot product?

Answer 7

the equation of your line will be of the form
r = (3,2,-1) + s*(a,b,c)
where (a,b,c) . (1,1,-2) = 0

Answer 8

ok im going to try that. thanks!