Mathematics
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OpenStudy (anonymous):
Rewrite1-cos135/sin135 using a half angle identity
11 years ago
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OpenStudy (anonymous):
cos 67.5°
tan 67.5°
cos 270°
tan 270°
11 years ago
OpenStudy (anonymous):
iiiiiiiiiiiiiiiiiiiiiiiiiiiiddddddddddddddddddddddddddddddddddkkkkkkkkkkkkkkkkkkkkkkkkkkk
11 years ago
OpenStudy (anonymous):
@jdoe0001
11 years ago
OpenStudy (anonymous):
@texaschic101
11 years ago
OpenStudy (anonymous):
@pooja195
11 years ago
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OpenStudy (anonymous):
@bohotness
11 years ago
OpenStudy (anonymous):
@aaronq
11 years ago
OpenStudy (anonymous):
@jdoe0001
11 years ago
OpenStudy (anonymous):
@bohotness
11 years ago
OpenStudy (anonymous):
they scared of trig
11 years ago
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OpenStudy (anonymous):
@MilkNCookies
11 years ago
OpenStudy (anonymous):
lel but she is looking at the post maybe she can help
11 years ago
OpenStudy (bohotness):
yes
11 years ago
OpenStudy (anonymous):
Can u help him?
11 years ago
OpenStudy (bohotness):
:D mmhm this is too easy
11 years ago
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OpenStudy (anonymous):
YAY
11 years ago
OpenStudy (anonymous):
;(
11 years ago
OpenStudy (anonymous):
wht she gonna help D:
11 years ago
OpenStudy (anonymous):
that she thanks it is easy and I dont know where to start on this
11 years ago
OpenStudy (anonymous):
me either, @bohotness u still here?
11 years ago
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OpenStudy (bohotness):
yes lol hold on
11 years ago
OpenStudy (anonymous):
KK
11 years ago
OpenStudy (bohotness):
-_- did you too even try looking it up
11 years ago
OpenStudy (anonymous):
wait I might be able to help
11 years ago
OpenStudy (anonymous):
I try doing it with the formula
11 years ago
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OpenStudy (anonymous):
Salt
11 years ago
OpenStudy (anonymous):
is we simplifying?
11 years ago
OpenStudy (anonymous):
the thing is I been there
11 years ago
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OpenStudy (anonymous):
and It dont give you the answer
11 years ago
OpenStudy (anonymous):
1/2
11 years ago
OpenStudy (bohotness):
did you try look up their answer and keeping going?
11 years ago
OpenStudy (anonymous):
?
11 years ago
OpenStudy (bohotness):
his problem seems a bit far-fetched to me, because the exact values of this particular sin and cos are easily found.
You might know them: cos135°=−122√, sin135°=122√,
So the answer is 1 - - 1 = 2.
I cannot see how half-angle formulas would be of help here... .-. what is close to that
11 years ago
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OpenStudy (anonymous):
Im bout to close this thread
11 years ago
OpenStudy (bohotness):
its a god
11 years ago