help pleasee(:

Question

help pleasee(:

anonymous · Answer

Solve 3x^2 + x + 10 = 0. Round solutions to the nearest hundredth. (4 points)
 	
	
x ≈ -2.83 and x ≈ 0.83
	
No real solutions

x ≈ -2.01 and x ≈ 1.67
	
x ≈ -1.67 and x ≈ 2.01

misty1212 · Answer

HI!!

anonymous · Answer

If their is dimond ?'s just refresh(:

misty1212 · Answer

looks like a job for the quadratic formula
do you know it?

anonymous · Answer

hii(: and no :/

misty1212 · Answer

then you can't do it !

misty1212 · Answer

the solution to 
$$ax^2+bx+c=0$$ is 
$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$

misty1212 · Answer

in your case $a=3,b=1,c=10$ plug them in and use a calculator because they want the decimal approximation

misty1212 · Answer

onoh since you have to use a calculator anyways, you might as well cheat and use it from the start http://www.wolframalpha.com/input/?i=3x%5E2+%2B+x+%2B+10+%3D+0

anonymous · Answer

ok. what part on there Should I be looking at?

anonymous · Answer

@misty1212

misty1212 · Answer

you can see that the graph lies entirely above the x axis
that means it never crosses or touches the x axis
that means it is never zero
no solution

anonymous · Answer

Thaank you.

misty1212 · Answer

$$\color\magenta\heartsuit$$