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Simplify. (k^7)^3 A) k^-10 B) k^4 C) k^10 D) k^21
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@Love_Ranaa
distributive property
\[\huge (x^n)^m = x^{m\cdot n}\]
Yep, multiply the exponent on the outside to all of the exponents on the inside.
Mulitiply the Exponents: \[7*3 = ?\]
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21
Yes, so what's our final answer?
Yes
So D
Correct
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Yes
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Thank you guys!
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