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OpenStudy (bananas1234):
. Evaluate 3 + √x + 7 - √3x when x = 9.
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OpenStudy (bananas1234):
the √ covers x + 7
OpenStudy (academicgurusinc):
Let's do this again!
OpenStudy (bananas1234):
and 3x
OpenStudy (bananas1234):
ok!
OpenStudy (academicgurusinc):
So let me simplify it for you.
3+Sqrt(9+7)-Sqrt(8x9) .... What do you get?
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OpenStudy (bananas1234):
3 + 4.123 - 5.196
OpenStudy (academicgurusinc):
Don't get to the decimals! Just tell me in the radical format.
OpenStudy (academicgurusinc):
so we'll have 3+sqrt(16)-Sqrt(72) .... Right?
OpenStudy (academicgurusinc):
Sorry sorry should be 3+sqrt(16)-Sqrt(27)
OpenStudy (bananas1234):
ok.. 3 + √16 - √27
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OpenStudy (academicgurusinc):
Yup! Now Simplify!
OpenStudy (bananas1234):
3 + 4.123 - 5.196
OpenStudy (academicgurusinc):
Well... Square root of 16 is just 4! So 3+4-Sqrt(27) ... From there we'll get 7+sqrt(27)
OpenStudy (bananas1234):
ok
OpenStudy (bananas1234):
so 7 + 2?
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OpenStudy (academicgurusinc):
We can even go more... Now we can simplify \[\sqrt{27}\] so we'll have \[\sqrt{9*3}\] then we'll get \[7+3\sqrt{3}\] as our final answer :)
OpenStudy (bananas1234):
wouldnt it be 7 - 3√3?
OpenStudy (academicgurusinc):
Actually you right... it's - ... didn't see it!
OpenStudy (bananas1234):
ok np!
OpenStudy (academicgurusinc):
so 7-\[3\sqrt{3}\]
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OpenStudy (bananas1234):
OK now i need the same question in decimal form.
OpenStudy (academicgurusinc):
Alright great... So let's go back to our original problem!
OpenStudy (academicgurusinc):
so we got \[7-\sqrt{2}\]
OpenStudy (academicgurusinc):
...... Sqrt(27) i meant
OpenStudy (bananas1234):
ok
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OpenStudy (triciaal):
|dw:1426659682401:dw|
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