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Mathematics 10 Online
OpenStudy (anonymous):

MEDALS!! ILL GET MY FRIEND TO FAN YOU! Which figures can be used to find the area of the composite figure? Choose exactly two answers that are correct. A. a semicircle with an area of 4.5Pi m2 B. a semicircle with an area of 18 PI m2 C. a rectangle with an area of 33 m2 D. a rectangle with an area of 66 m2 http://static.k12.com/calms_media/media/1571000_1571500/1571275/1/e519ed5deb61e1623a2ad3ca3191866ec7b0899e/MS_IMB-1401208-1110601.jpg PICTURE

OpenStudy (anonymous):

@amorfide @leonardo0430 @ParthKohli @phi @AnswerMyQuestions ??? WHOEVER CAN HELP ME

OpenStudy (anonymous):

@iGreen

OpenStudy (igreen):

Okay, the rectangle has a length of 11 and a width of 6, multiply both of them to find the area of the rectangle.

OpenStudy (anonymous):

The area of the rectangle is 66

OpenStudy (igreen):

Correct, so that's one of our answer.s

OpenStudy (igreen):

*answers.

OpenStudy (anonymous):

For the semi cirlce i cant figure out what

OpenStudy (anonymous):

because i know the area of circles

OpenStudy (igreen):

Area of a circle: \(A = \pi r^2\) \(A = 6^2\pi\)

OpenStudy (anonymous):

R*R*PI

OpenStudy (igreen):

Just find the area then divide by 2

OpenStudy (anonymous):

i did.

OpenStudy (anonymous):

3*3 = 9 * 3.14 = 28.26

OpenStudy (anonymous):

3 is the radius

OpenStudy (igreen):

Right

OpenStudy (igreen):

But it wants it in terms of pi

OpenStudy (igreen):

\(\dfrac{9 \pi}{2}\)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

28.274333882308139146163790449516 / 2 = 14.137166941154069573081895224758

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

It was A and D

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