Question

Kayla designed a rectangular patio that was 3 times as long as it was wide and had a perimeter of 160 feet.



What was the area of the patio?



A.


600 ft2


B.


1200 ft2


C.


1800 ft2


D.


2400 ft2

Answer 1

@perl

Answer 2

@Data_LG2

Answer 3

@iGreen

Answer 4

@XoALIEoX

Answer 5

P = 2L + 2W
L = 3W (because it's 3 times longer than it is wide)

Sub L into your expression for P to solve for W,

P = 2L + 2W
P = 2(3W) + 2W
P = 8W
W = P / 8
W = 160 ft / 8
W = 20 ft

Since you have W, you can solve for L,

L = 3W
L = 3(20 ft)
L = 60 ft

Now you can find the area,

A = LW
A = (60 ft)(20 ft)
A = 1200 ft²

Taken from:
https://answers.yahoo.com/question/index?qid=20130606183730AAXgDv8

Answer 6

Thank you!

Answer 7

^^^ @undeadknight26 explained it and showed you how to XD beat me to it

Answer 8

Any time dawg
#GoogleFtw