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Mathematics 22 Online
OpenStudy (hulkart):

http://openstudy.com/users/srinuscoobyWhich event below is independent of event A? A: You get to work on time. There are no accidents on the road. It's snowing outside. You remember to pick up milk on the way home. Your alarm goes off.

OpenStudy (anonymous):

B

OpenStudy (anonymous):

A and B wil be answer mostly.

OpenStudy (hulkart):

ok man, you're the BEST!!!

OpenStudy (anonymous):

Give more priority to B, but A also can happen, so that be it.

OpenStudy (anonymous):

What is the next question? How many questions today?

OpenStudy (hulkart):

*Theres a line over all these A's, I couldn"t type it...so i used (/) Which is NOT true for any event A? P(A/)+P(A)=1 P(A)+1-P(A) P(A/)=1-P(A) P(A/)+1=P(A)

OpenStudy (anonymous):

you messed up the second option.

OpenStudy (hulkart):

YES! how did you know!!!!!! P(A)=1-P(A/) It's good now

OpenStudy (anonymous):

P(A/)+1=P(A) is not true for any event A. (Fourth ONE in that)

OpenStudy (hulkart):

A tourist in France wants to visit 12 different cities. How many different routes are possible? 39,916,800 479,001,600 12 144

OpenStudy (anonymous):

It's 12! the answer.

OpenStudy (anonymous):

479,001,600. Why we fell into Permutation Combinations today?

OpenStudy (anonymous):

check your messages, i messaged you something

OpenStudy (hulkart):

A coin is flipped 3 times and the number of times heads appears is recorded. How many different outcomes can occur? 4 1 8 2 We are done with yesterdays test...I'll tell you how we did after this one then we'll continue, but this time 15 questions instead of 30....THANK YOU, IF ONLY YOU KNEW HOW MUCH I APPRECIATE YOUR HELP>>>

OpenStudy (anonymous):

any thing mentioned about no event is repeated?

OpenStudy (hulkart):

no.

OpenStudy (anonymous):

I think it is heads and tales recorded, in that problem.

OpenStudy (anonymous):

For three tosses of the coin all the possible outcomes are: . H-H-H T-H-H H-T-H H-H-T T-H-T T-T-H H-T-T T-T-T hence, according to your problem, the answer should be 7 as TTT should not come into consideration. So there might be an error in the question i'm guessing. Mark 8 for now.

OpenStudy (anonymous):

next problem ?

OpenStudy (anonymous):

Hurry up !

OpenStudy (hulkart):

For the function given, state the middle line: ƒ(t) = 3 cos(π t − 1).

OpenStudy (hulkart):

y=0 y=3 y=pai y=-1

OpenStudy (anonymous):

y=0

OpenStudy (hulkart):

For the given function, state the amplitude and the minimum output for the function: f (t)=3 cos[t+pai/6]

OpenStudy (anonymous):

amplitude is 3

OpenStudy (hulkart):

...and the minimum?

OpenStudy (anonymous):

you type next question and post it. I will tell u minimum in the mean time.

OpenStudy (hulkart):

For the function given, state the period: f (t)=6 sin [3t-pai/6]-1

OpenStudy (anonymous):

minimum for that previous problem is -3

OpenStudy (hulkart):

Find the reference angle given: t = 105°. 75° 15° 45° 85°

OpenStudy (anonymous):

period is 2 for the before problem.

OpenStudy (anonymous):

Find the reference angle given: t = 105°. 75° is the answer.

OpenStudy (hulkart):

2pai/3?

OpenStudy (anonymous):

yep 2pi/3

OpenStudy (hulkart):

funny how you put pi instead of pai, It shows how dumb I am Given cscθ = 3, find cos(θ).

OpenStudy (hulkart):

given csc theta

OpenStudy (anonymous):

csc means cosecent or cos?

OpenStudy (hulkart):

cosecant

OpenStudy (anonymous):

cos(θ) = \[2\sqrt{2}/3\] in quadrant 1 cos(θ) = \[-2\sqrt{2}/3\] in quadrant 2

OpenStudy (hulkart):

well done! Givencos theta=4/5 , find cot(θ).

OpenStudy (anonymous):

Told out there also. its 4/3

OpenStudy (hulkart):

Find the value of the trigonometric function sin (t) if sec t=-4/3 and the terminal side of angle t lies in quadrant II.

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