Find all rational roots of 2x^3 - 7x^2 + 9 = 0.
do you know p/q method ?
@Nnesha - no, sorry.
\[\huge\rm \frac{ p }{ q } =\frac{ constant }{ leading ~cofficient }\] what is constant and leading coefficient in that equation ??
the constant term is 9 and the leading cofficient is 2.
yes right so p represent constant q = leading coefficient so you ahve \[\frac{ 9 }{ 2 } = \frac{ \pm 1, ??? }{ ? }\] now factor both 9 and 2 write with plus minus sign for example 1
9 = 1, 2 ,3 2 = 1, 2
yep and 9 too
so you ahve \[\huge\rm \frac{ 9 }{ 2 } = \frac{ \pm 1, \pm 3 , \pm 9??? }{ \pm 1 , \pm 2}\] 2 is not a factor of 9
now write everything in fraction form |dw:1426717461527:dw| for example 1 divide by both 1 nd 2 which is at the denominator \[\huge\rm \frac{ \pm 1 }{ \pm 1 } ,\frac{ \pm 1 }{ \pm 2}\]
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