Question

How do i solve this

Answer 1

\[8x-14 = x^2 +1\]

Answer 2

This is a Quadratic Equation
\(8x-14=x^2+1\\ x^2-8x+15=0\)

Answer 3

You have a quadratic equation in the form: \(ax^2 + bx + c = 0\), then
use Bhaskara equation:
\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]