Question

Medal!!! Solve 4((cos(3x-(pi/6))^2))-3=0, when -pi<=x<=pi.

Answer 1

add 3, divide by 4, take the square root and you start with
\[\cos(3x-\frac{\pi}{6})=\pm\frac{\sqrt3}{2}\]

Answer 2

solve that for \(3x-\frac{\pi}{6}\) then solve the result for \(x\)