Question

CALC HELP CONTINUATION (:

Answer 1

What do you need help with?

Answer 2

@perl (:

Answer 3

Integrating a velocity gives you a position

Answer 4

Integrate the function and then evaluate it from 0 to 2

Answer 5

here we need distance, not the same as displacement

Answer 6

$$
\Large {displacement = \int_0^2 v(t)~dt~\\
distance = \int_0^2 |v(t)|~dt~\\

}
$$

Answer 7

i got 6, could you verify please?(:

Answer 8

$$
\Large {
distance =\\ \int_0^2 |v(t)|~dt~
=\int_0^2 |6t^2 - 18t + 12|~dt~\\
}
$$

Answer 9

6 is correct, I assume you did it on paper

Answer 10

yes(: thank you !!