challenge 2. how many tennis balls can fit into the container.
container: d=13 h=36 v=(3.14)(r^2)(h)
v= (3.14)(6.5^2)(36)
v=(3.14)(1521)
v=4775.94

cone(on top of the container) d=13 h=8 v=1/3(3.14)(6.5^2)(8)
v=(3.14)(338)/3
v=353.77

tennis balls d=2.63
v=4/3(3.14)(1.315^3)
v=4(7.14)/3
v=9.52

now we add the cone with the cylinder
353.77+4775.94=5129.71/9.52=538.83 balls would fit in the container?

Question

challenge 2. how many tennis balls can fit into the container. 
container: d=13 h=36 v=(3.14)(r^2)(h) 
v= (3.14)(6.5^2)(36)
v=(3.14)(1521)
v=4775.94

cone(on top of the container) d=13 h=8 v=1/3(3.14)(6.5^2)(8) 
v=(3.14)(338)/3
v=353.77

tennis balls d=2.63
v=4/3(3.14)(1.315^3)
v=4(7.14)/3
v=9.52

now we add the cone with the cylinder
353.77+4775.94=5129.71/9.52=538.83 balls would fit in the container?

rizags · Answer

does the container include both the cone and the cylinder?

anonymous · Answer

attachment

rizags · Answer

ur math looks right, u just need to round down to 538 balls because you cant have a decimal amount of balls.

anonymous · Answer

okay by any chance can you help me round?
 i am horrid at it

anonymous · Answer

would it be 539

rizags · Answer

538.8 would NORMALLY round UP to 539, BUT here we are dealing with physical materials and thus we have to round DOWN to 538

anonymous · Answer

oh okay thanks so much :)