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WILL GIVE A MEDAL AND FAN Find the area of a triangle whose base is 2 squareroot 3 in. and height is 3 squareroot 3 in. A. 3 squareroot 3 in. ^2 B. 6 squareroot 3 in. ^2 C. 9 in. ^2 D. 18 in. ^2
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i would do it but...... I HAVE TOO MUCH HW!!! T^T
ok, you can combine the 3 and the 2 that are before the sqrt(3) giving you 6sqrt(3) but the area of a triangle is 1/2 base * height so you need to half the 6, giving you 3sqrt(3)!
so you would get a.
now can someone help me with integrals?
Thank you so much!
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