Question

Find the horizontal force required to keep a small box of mass 200g at rest on a smooth plane inclined at 30 degrees to the horizontal gardiner

Answer 1

@shamim?

Answer 2

Forget the gardiner

Answer 3

Csn u draw it???

Answer 4

I think

Answer 5

U know the weight w=mg=0.2*9.8=?

Answer 6

Yup. W=1.96N

Answer 7

Yes u r right!!!

Answer 8

Now what? I found that Fp is 0.98N

Answer 9

Now component of w along inclined plane
=1.96*sin30=?

Answer 10

0.98N

Answer 11

So we need to apply 0.98N along the inclined plane up to make the object stationary

Answer 12

We hv to find out the horizontal force. Right?

Answer 13

Yup

Answer 14

Let the horizontal applied force =F

Answer 15

Ok

Answer 16

Component of F along the inclined plane is=0.98N

Answer 17

Yes

Answer 18

So we can write
F*cos30=0.98
F=?

Answer 19

\[F=\frac{0.98}{cos(30)}\]?

Answer 20

That works! THANK YOU. But why divide by cos(30)?

Answer 21

F*3=9
F=9/3
Right?

Answer 22

F*cos30=0.98
F=0.98/cos30
Right?

Answer 23

Exactly. But why could we say F = 0.98*cos(30)?

Answer 24

Is it because the force itself is horizontal, its just that part acts up the plane?

Answer 25

F is along horizontal. So the inclined plane makes angle with horizontsl is=30 degree?

Answer 26

Yes

Answer 27

Did u get it??!

Answer 28

I see. Thanks alot :D

Answer 29

U r most welcome!!!!

Answer 30

Fanned as well :). Got to go to sleep. Night :)

Answer 31

I m also enjoyed a lot!!!!!!!

Answer 32

Anywsy frm where u r???!! Usa??

Answer 33

@shamim, Australia :D