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Which of the following is a solution |x-8| less than or equal to 14
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\[|x-8|\le14\]
A. x = 6 B. x = 22 C. x = –4 D. x = 0
those are my choices
so, that would be giving you either that\[x-8\le14\]or, \[x-8\ge-14\] so your solution set (or the equation to find it) would be given this way:
\[-14 \le x-8 \le 14\]
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now, add 8 to each piece\[-14 \color{red}{+8}\le x-8\color{red}{+8} \le 14\color{red}{+8}\] what do you get, can you tell me?
-6 22
16
my answer wld be 22 rite
the answer would be \[-6 \le x \le 22\]
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saying that x can be any [real] number from (and including) -6 ---> till (and including) 22.
In interval notation this can be written as\[x~ \color{red}{\in}~[-6,22]\]
thank you
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