A box has 5 beads of the same size, but all are different colors. Tina draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tina would pick a red bead on the first draw, then a green bead, and finally a red bead again?
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OpenStudy (anonymous):
@deadpoolroxz @iGreen
OpenStudy (anonymous):
@deadpoolroxz
OpenStudy (anonymous):
u there?
OpenStudy (anonymous):
@deadpoolroxz
OpenStudy (anonymous):
@iGreen
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OpenStudy (anonymous):
ill join
the deadpool club but how
OpenStudy (anonymous):
lol then ill mention u in every question
OpenStudy (igreen):
Okay, 5 beads, 5 different colors.
OpenStudy (igreen):
What's the probability of picking a red?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
1 of 5?
OpenStudy (anonymous):
is it righT?
OpenStudy (igreen):
Correct, what about picking a green?
OpenStudy (anonymous):
1 of 5
OpenStudy (igreen):
Correct, and another red is 1/5
\(\dfrac{1}{5} \times \dfrac{1}{5} \times \dfrac{1}{5} \)
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OpenStudy (anonymous):
right
OpenStudy (igreen):
Multiply.
\(\dfrac{1}{5 \times 5 \times 5}\)
OpenStudy (igreen):
5 * 5 * 5 = ?
OpenStudy (anonymous):
15
OpenStudy (anonymous):
well u take a while to type
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OpenStudy (anonymous):
cant blam
OpenStudy (anonymous):
lol anyone give me an answer
OpenStudy (anonymous):
thank you dead pool heex for the medal
OpenStudy (anonymous):
you wecome you earnd it
OpenStudy (igreen):
That's wrong.. @pandaluvs
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OpenStudy (igreen):
5 * 5 * 5 isn't 15..
OpenStudy (anonymous):
@iGreen sorry i said it wrong
OpenStudy (anonymous):
125
OpenStudy (anonymous):
exactly
OpenStudy (anonymous):
thats it
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