Question

@Nnesha http://prntscr.com/6jaep0

Answer 1

huh

Answer 2

b n c

Answer 3

Are you sure ?

Answer 4

@Nnesha, Can you please check ?

Answer 5

do you know the equation for direct variation ??

Answer 6

huh im confused

Answer 7

\(\bf \large {\begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{\color{brown}{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{\color{brown}{ n}}&\cdot&x
\\\hline\\
&& y={\color{brown}{ n }}x
\end{array}\\ \quad \\
y=-8\qquad x=4\implies -8={\color{brown}{ n }}4\impliedby \textit{solve for }n
}\)

Answer 8

nnesha can you help me understand

Answer 9

What just happened...
I think someone is on my acc, How do you remember these stuff @Nnesha And thsi is my sisters homework

Answer 10

It's been a while.

Answer 11

huh ??

Answer 12

okay so i guess i don't have to do it
he already explained it :)

Answer 13

I'm still confused...

Answer 14

equation for direct variation is y = kx
replace y and x by their values

Answer 15

replace y by -8 and x by 4 then solve for k