@Nnesha http://prntscr.com/6jaep0

Question

jordan123321 · Answer

huh

princeharryyy · Answer

b n c

iluvsoccer · Answer

Are you sure ?

iluvsoccer · Answer

@Nnesha, Can you please check ?

nnesha · Answer

do you know  the equation for direct variation ??

lilshane · Answer

huh im confused

jdoe0001 · Answer

$\bf \large {\begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\ \quad \
\textit{something}&=&{\color{brown}{ \textit{some value}}}&\cdot &\textit{something else}\ \quad \
y&=&{\color{brown}{ n}}&\cdot&x
\\hline\
&&  y={\color{brown}{ n }}x
\end{array}\ \quad \
y=-8\qquad x=4\implies -8={\color{brown}{ n }}4\impliedby \textit{solve for }n
}$

lilshane · Answer

nnesha can you help me understand

iluvsoccer · Answer

What just happened...
I think someone is on my acc, How do you remember these stuff @Nnesha And thsi is my sisters homework

iluvsoccer · Answer

It's been a while.

nnesha · Answer

huh ??

nnesha · Answer

okay so i guess i don't have to do it
 he  already explained it :)

iluvsoccer · Answer

I'm still confused...

nnesha · Answer

equation for direct variation  is y = kx 
replace y and x by their values

nnesha · Answer

|dw:1426891560542:dw|
replace y by -8 and x by 4  then solve for k