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find the area of the surface formed by revolving r=e^6(theta) about the axis theta=pi/2 over the interval 0
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hmm .-. take a picture of your question it prob translated into words instead of hows its suppose to be
btw that would be nice if you did that makes it alot easier
its worded the same way as i typed it in @TheAlgebraHelper
huh hmm @perl @hero can you guys help?
@freckles could you help me real quick with this problem
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