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rvc (rvc):
u ,v,w non-coplanar vectors then
(u+v-w).[(u-v)x(v-w)]=
rvc (rvc):
A)0
B)u.(v x w)
C)u.(w x v)
D)3u.(v x w)
rvc (rvc):
@divu.mkr
OpenStudy (anonymous):
Just for the purpose of solving , assume u , v and w vectors as i+j , j , j+k ...I chose them because u-v=i and v-w=-k , so easy to plug values and get answer ..i got it as D..thinking of the proper method..
rvc (rvc):
nope
the ans is B
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rvc (rvc):
i want to know the working
OpenStudy (anonymous):
Yep , B ..i made a calculation error
rvc (rvc):
show me the working pls
OpenStudy (anonymous):
By this method of assuming values ?
I am still thinking about the "proper" method
rvc (rvc):
yep
i want to know
@divu.mkr will tell me
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OpenStudy (anonymous):
|dw:1426944476407:dw|
rvc (rvc):
okaay
rvc (rvc):
@divu.mkr start
OpenStudy (anonymous):
isnt it simple dot and cross??
rvc (rvc):
how to expand
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rvc (rvc):
say
OpenStudy (anonymous):
normal expressions of dots and crosses..
cross --> uXv - uXw + vXw
now take dot with every term outside
just 3 terms will be there
OpenStudy (anonymous):
I thought it would be very lengthy to expand ! Turns out it wasn't lengthy at all ! :)