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Will Medal 3surd((x+2)^3,5)+3=27 copy and paste into wolframalpha.com and you'll see the equation.
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\[3\sqrt[5]{(x+2)^3}+3=27\]
are you solving for x?
Yes
firstly divide both sides by 3
we get this right? \[(\sqrt[5]{(x+2)^3})/3+1=9\]
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yes
i think
|dw:1426963493310:dw|
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