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Algebra
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2. Factor out the GCF: r^3+3r^2+4r a. r(r^2+3r+4) b. r^2 (r+3r+4) c. r^2 (r^2+3r+4) d. r(r^3+3r^2+4r)
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\(\bf r^3+(3r)^2+4r\implies r^3+(3^2r^2)+4r \\ \quad \\ r{\color{red}{ r}}r+33{\color{red}{ r}}r+4{\color{red}{ r}}\)
from the solution, the answer is A
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